8086 Program to add two 8 bit Hexadecimal numbers microprocessor

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I have come up with a new code for you today.

We will  see a code in order to add two 8 bit hexadecimal numbers using microprocessor 8086 . The code is attached to below and also do check out other topics like Android , C programming , etc on your blog☺ !!

8086 program to add two 8-bit hexadecimal numbers source code :-

data segment

num1 db 50h

num2 db 30h

sum db ?

data ends

code segment

start :

assume cs:code, ds:data

mov ax,data

mov ds,ax

mov al,num1

mov bl,num2

add al,bl

mov ah,4ch

int21h

code ends

end start

Block transfer OVERLAPPING 
Block transfer(Simple Program)
Block Transfer(REVERSE ORDER)
Addition of 8-bit  BCD8086 program
addition of 16-bit bcd program
Division of 32/16 bit program
Subtraction of 8-bit program
Subtraction of 8-bit BCD program
Subtraction of 16-bit program
Subtraction of 16-bit BCD program
String reverse 8086 program
block transfer using string
string concatenation
string length calculation
Block Transfer 
Block reverse
Hex to ASCII program 8086
BCD to ASCII program 8086
ASCII to BCD program 8086

BCD to HEX
HEX to BCD

Block transfer in reverse

Block transfer using STRING instruction

8086 Program to subtract two 16-bit BCD numbers MICROPROCESSOR 8086

8086 program to divide 8 bit hexadecimal number

8086 Program for Addition of two 8 bit Hexadecimal numbers microprocessor

8086 program to add two 8 bit BCD numbers

Assembly Language Program to DIVISION two 32-bit / 16 –bit numbers 8086 (signed and unsigned)

 

Programs:-

For many other Language Programs of microprocessor 8086, C++ , Data Structures , etc and MSBTE diploma,BCA, MCA and engineering related concepts visit our  BLOG

8086 program to add two 8 bit BCD numbers

8-bit BCD ADDITION 8086 program:-

data segment

num1 db 20h

num2 db 30h

sum db ?

data ends

code segment

start :

assume cs:code, ds:data

mov ax,data

mov ds,ax

mov al,num1

mov bl,num2

add al,bl

daa

mov ah,4ch

int21h

code ends

end start

Block transfer OVERLAPPING 
Block transfer(Simple Program)
Block Transfer(REVERSE ORDER)
Addition of 8-bit  BCD8086 program
addition of 16-bit bcd program
Division of 32/16 bit program
Subtraction of 8-bit program
Subtraction of 8-bit BCD program
Subtraction of 16-bit program
Subtraction of 16-bit BCD program
String reverse 8086 program
block transfer using string
string concatenation
string length calculation
Block Transfer 
Block reverse
Hex to ASCII program 8086
BCD to ASCII program 8086
ASCII to BCD program 8086
BCD to HEX
HEX to BCD

Block transfer in reverse

Block transfer using STRING instruction
8086 Program to subtract two 16-bit BCD numbers MICROPROCESSOR 8086

8086 program to divide 8 bit hexadecimal number

8086 Program for Addition of two 8 bit Hexadecimal numbers microprocessor

8086 program to add two 8 bit BCD numbers

Assembly Language Program to DIVISION two 32-bit / 16 –bit numbers 8086 (signed and unsigned)

 

 

Programs:-

For many other Language Programs of microprocessor 8086, C++ , Data Structures , etc and MSBTE diploma,BCA,MCA and engineering related concepts visit our  BLOG

8086 Assembly Program to Add two ASCII numbers

data segment

n1 db 1dup(?)

n2 db 1dup(?)

ascii1 db 1dup(?)

ascii2 db 1dup(?)

data ends

code segment

assume cs:code, ds:data

mov dx,data

mov ds,dx

mov bl,n2

mov al,n1

add al,bl

aaa

jnc nxt

mov ascii2,31h

nxt: add al,30h

mov ascii1, al

mov ah,4ch

int 21h

code ends

end start

string compare
sum of SERIES BCD numbers
Block reverse
Programs:-
For many other Assembly Language  Programs related to microprocessor 8086 , C++ , C, DataStructures visit our  BLOG 

There are programs of largest ,smallest ,division ,multiplication,odd/even,block operation ,string operations,BCD ,etc

Assembly Program 8086 to add two 8-bit BCD number and to add two 16-bit BCD number

Hey !! Let's see program to multiply two 8 bit numbers and another program to add two 16 bit BCD number. First let's take a look at the theory.

Let's go!!

In assembly language 8086 we use mnemonics in order to perform arithmetic operations like ADD/ADC in addition.
So, Let's dive deep into what ADD and ADC is ....Scroll Down for Program↓...

ADD:- It adds number from source to destination without carry. Source can be memory location or register or a number but destination should be register or a memory location(not immediate number). Remember that source and destination should be of same type and both shouldn't be memory locations.

Syntax: ADD <destination> <source>
Operation: destination← destination + source

ADC:- It adds number from source to destination with carry i.e , adds carry flag into result of addition. Source can be memory location or register or a number but destination should be register or a memory location(not immediate number). Remember that source and destination should be of same type and both shouldn't be memory locations.

Syntax: ADC <destination> <source>
Operation: destination← destination + source + carry

DAA:- Usually used after ADD/ADC because DAA works on AL registers. This instruction is used to convert result of addition of 2packed numbers into 1-packed BCD number. in simple language, ADD/ADC adds BCD number in hexadecimal format and then DAA instruction converts this hexadecimal result into BCD result.

Syntax: DAA

Which flags get affected?
Ans- OF , CF, PF , AF, SF , ZF .



Below are 2 programs : Two 8-bit BCD addition and Two 16-bit BCD addition.

Sum of two 8-Bit BCD numbers using ALP 8086 :-

data segment

no1 db 02h

no2 db 03h

ans db ?

data ends

code segment

start : assume  cs :code,  ds :data

mov ax ,data

mov ds , ax

mov al , no1

mov bl ,no2

ADD al, b1

DAA

mov ans ,al

mov ah ,4ch

int 21h

code ends

end start

Sum of two 16-Bit BCD numbers using ALP 8086 :-

data segment

no1 dw 21h

no2 dw 31h

ans dw ?

data ends

code segment

start : assume  cs :code,  ds :data

mov ax ,data

mov ds , ax

mov ax , no1

mov bx , no2

ADD ax , bx

DAA

mov ans ,ax

mov ah ,4ch

int 21h

code ends

end start

Programs:-

For many other Assembly Language  Programs related to microprocessor 8086 , data structure, etc Subjects  related to MSBTE,Computer engineering, IT field visit our  BLOG 

There are programs of largest ,smallest ,division ,multiplication,odd/even,block operation ,string operations,BCD ,etc

Assembly 8086 program for addition of two 16-bit numbers

In assembly language 8086 we use mnemonics in order to perform arithmetic operations like ADD/ADC in addition.

So, Let's dive deep into what ADD and ADC is ...

ADD:- It adds number from source to destination without carry. Source can be memory location or register or a number but destination should be register or a memory location(not immediate number). Remember that source and destination should be of same type and both shouldn't be memory locations.

Syntax: ADD <destination> <source>
Operation: destination← destination + source

ADC:- It adds number from source to destination with carry i.e , adds carry flag into result of addition. Source can be memory location or register or a number but destination should be register or a memory location(not immediate number). Remember that source and destination should be of same type and both shouldn't be memory locations.

Syntax: ADC <destination> <source>
Operation: destination← destination + source + carry

Which flags get affected?
Ans- OF , CF, PF , AF, SF , ZF .

data segment

no1 dw 21h

no2 dw 31h

ans dw ?

data ends

code segment

start : assume  cs :code,  ds :data

mov ax ,data

mov ds , ax

mov ax , no1

mov bx , no2

ADD ax , bx

mov ans ,ax

mov ah ,4ch

int 21h

code ends

end start

Programs:-


For many other Assembly Language  Programs related to microprocessor 8086 visit our  BLOG 

There are programs of largest ,smallest ,division ,multiplication,odd/even,block operation ,string operations ,etc

Assembly Program 8086 - Addition of two 8-bit numbers

In assembly language 8086 we use mnemonics in order to perform arithmetic operations like ADD/ADC in addition.
So, Let's dive deep into ADD and ADC ...Scroll Down for Program Code

ADD:- It adds number from source to destination without carry. Source can be memory location or register or a number but destination should be register or a memory location(not immediate number). Remember that source and destination should be of same type and both shouldn't be memory locations.

Syntax: ADD <destination> <source>
Operation: destination← destination + source

ADC:- It adds number from source to destination with carry i.e , adds carry flag into result of addition. Source can be memory location or register or a number but destination should be register or a memory location(not immediate number). Remember that source and destination should be of same type and both shouldn't be memory locations.

Syntax: ADC <destination> <source>
Operation: destination← destination + source + carry

Which flags get affected?
Ans- OF , CF, PF , AF, SF , ZF .


data segment

no1 db 02h

no2 db 03h

ans db ?

data ends

code segment

start : assume  cs :code,  ds :data

mov ax ,data

mov ds , ax

mov al , no1

mov bl ,no2

ADD al, b1

mov ans ,al

mov ah ,4ch

int 21h

code ends
end start

Addition / sum of two 16 bit nos

Multiply 8-bit numbers(unsigned)
Multiply 16-bit numbers(signed)
Subtract 8-bit numbers