8086 Assembly Program to MULTIPLY two 8-bit numbers(signed and unsigned)

Hey Guys!! Today we will see 8086 program to multiply two 8-bit number using the signed and unsigned method. Before proceeding let's see and understand the theory first and then move further with the program. 

Let's go!!

In assembly language 8086 we use mnemonics in order to perform arithmetic operations like  in MUL/IMUL subtraction.
So, Let's dive deep into what  MUL and IMUL is ...


MUL:- It multiplies unsigned byte/word from source with unsigned byte/word in AL/AX register.
Operation:-
When source is BYTE  then, AX← AL* unsigned 8-bit source
When source is BYTE  then, DX: AX← AX* unsigned 16-bit source


IMUL:- It multiplies signed byte/word from source with signed byte/word in AL/AX register.
Operation:-
When source is BYTE  then, AX←  AL* signed 8-bit source
When source is BYTE  then, DX: AX←  AX* signed 16-bit source


Which flags get affected?
Ans- OF , CF, PF , AF, SF , ZF .



Unsigned:- 

data segment

no1 db 02h

no2 db 03h

ans db ?

data ends

code segment

start : assume  cs :code,  ds :data

mov ax ,data

mov ds , ax

mov al , no1

mov bl ,no2

MUL  b1

mov ans ,al

mov ah ,4ch

int 21h

code ends

end start

Signed:-

data segment

no1 db 02h

no2 db 03h

ans db ?

data ends

code segment

start : assume cs :code, ds :data

mov ax ,data

mov ds , ax

mov al , no1

mov bl ,no2

imul b1

mov ans ,al

mov ah ,4ch

int 21h

code ends

end start

block transfer OVERLAPPING 

Block transfer(Simple Program)

Block Transfer(REVERSE ORDER)

Addition of 8-bit  BCD8086 program

addition of 16-bit bcd program

Division of 32/16 bit program

Subtraction of 8-bit program

Subtraction of 8-bit BCD program

Subtraction of 16-bit program

Subtraction of 16-bit BCD program

Multiply 8-bit numbers(unsigned)

Addition of 8-bit number

Programs:-


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