Assembly 8086- program to multiply two 16-bit nos

In assembly language 8086 we use mnemonics in order to perform arithmetic operations like  in MUL/IMUL subtraction.
So, Let's dive deep into what  MUL and IMUL is ...

MUL:- It multiplies unsigned byte/word from source with unsigned byte/word in AL/AX register.
Operation:-
When source is BYTE  then, AX← AL* unsigned 8-bit source
When source is BYTE  then, DX: AX← AX* unsigned 16-bit source

IMUL:- It multiplies signed byte/word from source with signed byte/word in AL/AX register.
Operation:-
When source is BYTE  then, AX←  AL* signed 8-bit source
When source is BYTE  then, DX: AX←  AX* signed 16-bit source

Which flags get affected?
Ans- OF , CF, PF , AF, SF , ZF .

data segment

no1 db 02h

no2 db 03h

ans db ?

data ends

code segment

start : assume  cs :code,  ds :data

mov ax ,data

mov ds , ax

mov al , no1

mov bl ,no2

imul  b1

mov ans ,al

mov ah ,4ch

int 21h

code ends

end start

block transfer OVERLAPPING 

Block transfer(Simple Program)

Block Transfer(REVERSE ORDER)

Addition of 8-bit  BCD8086 program

addition of 16-bit bcd program

Division of 32/16 bit program

Subtraction of 8-bit program

Subtraction of 8-bit BCD program

Subtraction of 16-bit program

Subtraction of 16-bit BCD program

Programs:-

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